-16x^2+144x=260

Solution for -16x^2+144x=260 equation:

-16x^2+144x=260

We move all terms to the left:

-16x^2+144x-(260)=0

a = -16; b = 144; c = -260;
Δ = b2-4ac
Δ = 1442-4·(-16)·(-260)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-64}{2*-16}=\frac{-208}{-32}
=6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+64}{2*-16}=\frac{-80}{-32}
=2+1/2
$